Asked by peter
                A dynamite blast sends a piece of rock (shatter) straight upwards.  After 2.31x10^0 s the piece of rock has a velocity of 1.56x10^1 m/s.  Assuming there is no air resistance, what is the initial velocity of the rock, to two significant figures? 
            
            
        Answers
                    Answered by
            drwls
            
    V(t) = Vo - g*t
Solve for Vo, knowing that V(t) = 15.6 m/s when t = 2.31 s. Use g = 9.81 m/s^2
Vo = 15.6 + 9.81*2.31 = ___
You do the math.
    
Solve for Vo, knowing that V(t) = 15.6 m/s when t = 2.31 s. Use g = 9.81 m/s^2
Vo = 15.6 + 9.81*2.31 = ___
You do the math.
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