Asked by LOL

A geosynchronous satellite is one that appears to be fixed in the sky, a condition useful for telecommunications. If such a satellite orbits the earth at an altitude of 49500 km above the earth's surface, what is its centripetal acceleration? The radius of the Earth is about 6370 km.

Answers

Answered by Damon
R = 6,370,000 + 49,500,000 = 5.59 * 10^7 meters
omega = 2 pi / T = 2 pi /(24*3600) = 7.27 10^-5 radians/second
Ac = R omega^2 = 5.59^10^7 * 5.28 *10^-9 = 29.5 *10^-2 = 0.295 m/s^2

lets guess at g at that height
9.81 at R = 6.37*10^6
what at R = 4.95*10^7 ???
goes as 1/R^2
(6.37/49.5)^2 = 0.0166
0.0166 * 9.81 = 0.162 m/s^2
hmmm, g is not equal to Ac, check all my arithmetic
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