R = 6,370,000 + 49,500,000 = 5.59 * 10^7 meters
omega = 2 pi / T = 2 pi /(24*3600) = 7.27 10^-5 radians/second
Ac = R omega^2 = 5.59^10^7 * 5.28 *10^-9 = 29.5 *10^-2 = 0.295 m/s^2
lets guess at g at that height
9.81 at R = 6.37*10^6
what at R = 4.95*10^7 ???
goes as 1/R^2
(6.37/49.5)^2 = 0.0166
0.0166 * 9.81 = 0.162 m/s^2
hmmm, g is not equal to Ac, check all my arithmetic
A geosynchronous satellite is one that appears to be fixed in the sky, a condition useful for telecommunications. If such a satellite orbits the earth at an altitude of 49500 km above the earth's surface, what is its centripetal acceleration? The radius of the Earth is about 6370 km.
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