Asked by anna
A geosynchronous satellite is one that appears to be fixed in the sky, a condition useful for telecommunications. If such a satellite orbits the earth at an altitude of 33000 km above the earth's surface, what is its centripetal acceleration? The radius of the Earth is about 6370 km.
Answers
Answered by
Damon
r = 33*10^6 + 6.37*10^6
2 pi r = circumference of orbit
v = 2 pi r/(24 h * 3600 s/h)
Ac = v^2/r
2 pi r = circumference of orbit
v = 2 pi r/(24 h * 3600 s/h)
Ac = v^2/r
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