Question
A geosynchronous satellite is one that appears to be fixed in the sky, a condition useful for telecommunications. If such a satellite orbits the earth at an altitude of 33000 km above the earth's surface, what is its centripetal acceleration? The radius of the Earth is about 6370 km.
Answers
r = 33*10^6 + 6.37*10^6
2 pi r = circumference of orbit
v = 2 pi r/(24 h * 3600 s/h)
Ac = v^2/r
2 pi r = circumference of orbit
v = 2 pi r/(24 h * 3600 s/h)
Ac = v^2/r
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