A gaseous product of a reaction is collected at 280K and 0.95 atm. Given R=0.0821L⋅atmmol⋅K

Question

, what is the molar mass of the gas, in grams per mole, if 5.49 g of gas occupies 4.92 L?(1 point)
Responses

24 g/mol
24 g/mol

0.04 g/mol
0.04 g/mol

133 g/mol
133 g/mol

27 g/mol

Answer 1

To solve this problem, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in L)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in K)

We can calculate the number of moles of gas using the given information:

n = PV / RT
n = (0.95 atm * 4.92 L) / (0.0821 L·atm/mol·K * 280 K)
n = 0.217 mol

To find the molar mass of the gas, we can use the formula:

molar mass = mass / moles

We are given that the mass is 5.49 g and the number of moles is 0.217 mol, so we can calculate:

molar mass = 5.49 g / 0.217 mol
molar mass ≈ 25.35 g/mol

Therefore, the molar mass of the gas is 25.35 g/mol.