A chemical reaction occurring in a cylinder equipped with a movable piston produces 0.58 mol of a gaseous product. If the cylinder contained 0.11 mol of gas before the reaction and had an initial volume of 2.1 L, what was it's volume after the reaction.
Am I doing this right
V1/n1=V2/n2
I'm looking for V2
0.58 mol/0.11mol. 2.1L = 11.0L + 2.1L = 13L did I do this right
1 answer
Does the 0.11 mol there initially enter into the reaction? If not, then you are right at about 13L.
2 answers