A gaseous mixture of O2 and N2 contains 31.8 % nitrogen by mass. What is the partial pressure of oxygen in the mixture if the total pressure is 445 mmHg?

Answer 1

The partial pressure of the gasses reflects the mole ratios of the gasses.

http://en.wikipedia.org/wiki/Partial_pressure

Assume 100grams of gas. 31.8 grams is N2, or the moles of N2 is 31.8/28=1.14
The moles of O2 will be 68.2/32=2.15

pressureN2/PressureO2 =
X/(445-x)=1.14/2.15

2.15x=1.14(445-x)
3.29x=507
pressureN2=154
pressureO2=291mmHg

check my work.

Answer 2

your answer was correct!

Answer 3

it looks complicated, but substitute your own numbers and follow his math process and it all works out for correct answer.
my P=825mmHg and 36.8% N2 was worked correctly.

Answer 4

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Answer 5

I feel the chemistry between us ;)

Don't worry, I'm already measuring the noose...

Answer 6

So does this teacher just not read these like ever or is he a just smiling at all the attention he's getting

Answer 7

hello people from the past im in the futcure