A gas in a discharge tube consists entirely of ions of the same element, of the same charge. Each ion has only one remaining electron. The voltage between the electrodes of the gas discharge tube is increased from zero. Electrons are accelerated across the potential, and then hit the gaseous ions within the tube. These are called ballistic electrons. Below a threshold value of 91.9V the emission spectrum is completely blank. At a plate voltage of 91.9V the emission spectrum consists of a single line. Determine the chemical identity of the ion gas in the tube.

Question

Please enter the atomic number (Z) of the ion gas in the tube. For example, for hydrogen, please enter '1'.

Answer 1

la energia balistica es igual al cambio de energia de transicion.
qv= kz^2((1/nf^2)-(1/ni^2)))
solo hay una emision del espectro, entonces la energia balistica solo es capaz de exictar del estado n=1 al estado n=2:
qv= kz^2((1/2^2)-(1/1^2)))=3/4*kz^2
z=((1.641e-9*91.9)/(0.75*2.18e-18))^0.5
z=3, el gas es Li, Perdon por colocar la rpta en español, no soy muy bueno escribiendo en ingles

Answer 2

Muchas gracias mi amigo ;)

Answer 3

you are welcome !!