A gas cylinder containing 6.38 mol of neon has a pressure of 491 mm Hg at 295 K. If 3.22 mol of helium is added to this cylinder, at constant temperature and volume, what will be the pressure in the cylinder?

2 answers

PV=nRt

at constant volume and temp

P1/P2=n1/N2

P1=491mmHg*(6.38+3.22)/6.38
738.81