A gardener uses a wheelbarrow as a lever to lift some dirt. The energy applied by the gardener is 2,000 joules. The efficiency of the work done is 95%. How much work is done on the dirt?(1 point) Responses 1,905 joules 1,905 joules 2,000 joules 2,000 joules 2,105 joules 2,105 joules 1,900 joules

Answer 1

To find the work done on the dirt, we can use the formula for efficiency:

\[ \text{Efficiency} = \frac{\text{Work output}}{\text{Work input}} \times 100% \]

Given that the efficiency is 95% and the work input (energy applied by the gardener) is 2,000 joules, we can rearrange the formula to find the work output:

\[ \text{Work output} = \text{Efficiency} \times \text{Work input} \]

Substituting in the values, we convert the efficiency percentage to a decimal:

\[ \text{Work output} = 0.95 \times 2000 , \text{joules} \]

Calculating the work output:

\[ \text{Work output} = 1900 , \text{joules} \]

So, the work done on the dirt is 1,900 joules.