A team of students builds a lever as a science project. They expend 10,300 Joules of energy to lift some bricks with the lever. If 6,283 Joules of energy are applied to the bricks, what is the lever’s efficiency?(1 point)

Question

Responses

0.61%
0.61%

61%
61%

164%
164%

39%

Answer 1

To calculate the efficiency of the lever, you can use the formula:

\[ \text{Efficiency} = \left( \frac{\text{Useful Output Energy}}{\text{Input Energy}} \right) \times 100% \]

In this case:

• Useful Output Energy (energy applied to the bricks) = 6,283 Joules
• Input Energy (energy expended) = 10,300 Joules

Now, plug in the values:

\[ \text{Efficiency} = \left( \frac{6,283}{10,300} \right) \times 100% \]

\[ \text{Efficiency} = (0.6094) \times 100% \approx 60.94% \]

Rounding this gives approximately 61%.

So, the lever's efficiency is 61%.