A gardener pushes a lawn roller through a distance of 20 m. If he applies a force of 20 N in a direction inclined at 60° to the ground, find the work done by the gardener on the lawn mover

Answer 1

The work done by the gardener is given by:

W = Fd cosθ

where F is the force applied by the gardener, d is the distance covered by the lawn roller, and θ is the angle between the force and the direction of motion.

In this case, F = 20 N, θ = 60°, and d = 20 m. Therefore, the work done by the gardener is:

W = 20 N x 20 m x cos60°
W = 200 J

Therefore, the gardener has done 200 Joules of work on the lawn roller.

Answer 2

To find the work done, we need to find the component of the force in the direction of displacement. Since the force is inclined at 60° to the ground, we can find the horizontal component of the force using the following formula:

Horizontal component of force = Force * cos(angle)
F_horizontal = 20 N * cos(60°)

Since cos(60°) = 1/2:

F_horizontal = 20 N * (1/2) = 10 N

Now that we have the horizontal component of the force, we can find the work done using the formula:

Work done = Force x Distance
W = F_horizontal * Distance
W = 10 N * 20 m
W = 200 J

The work done by the gardener on the lawn roller is 200 Joules.