a fun loving 11.4kg otter slides up a hill and then back down to the same place. If she starts up at 5.75 m/s and returns at 3.75 m/s, how much mechanical energy did she lose on the hill and what happened to that energy

Answer 1

Figure the KE at start, subtract the KE at the finish, that is the friction loss.

Answer 2

so i did Ki= 1/2mv^2 = 1/2(11.4kg)(5.75 m/s)2 = 188.45 J

Kf= 1/2mv^2
1/2(11.4kg)(3.75m/s)2= 80.15 J

so I took 188.45 - 80.15 and got 108 J is this correct

Answer 3

yes

Answer 4

Thank you!