Xc = Xl = 2pi*F*L = 6.28*4100*0.32 = 8244 ohms.
C = 1/(2pi*F*Xc) = 1/(6.28*4100*8244) = 4.7*10^-9 farads = 0.0047 uF.
A fully charged capacitor and a 0.32-H inductor are connected to form a complete circuit. If the circuit oscillates with a frequency of 4.1 ✕ 103 Hz, determine the capacitance of the capacitor.
1 answer