A forklift lifts a 900-Newton load 5 meters high. It then carries this load to a horizontal distance of 20 meters. Determine the total work done on the load.

1 answer

The work done on an object is equal to the force applied on it multiplied by the distance it is moved.

The work done to lift the load to a height of 5 meters is given by the equation work = force * distance:
work = 900 N * 5 m = 4500 Joules

The work done to carry the load horizontally for 20 meters is also given by the equation work = force * distance:
work = 900 N * 20 m = 18000 Joules

Therefore, the total work done on the load is 4500 Joules + 18000 Joules = 22500 Joules.