The work done on an object is given by the equation:
Work = Force * Distance * cos(theta)
Where:
- Force is the magnitude of the force applied to the object (in newtons)
- Distance is the distance over which the force is applied (in meters)
- theta is the angle between the force vector and the displacement vector (in degrees)
In this case, the forklift lifts the load vertically, so theta = 0 degrees (since the force vector is parallel to the displacement vector).
Work = 900 N * 5 m * cos(0 degrees)
Work = 900 N * 5 m * 1
Work = 4,500 Joules
Therefore, the total work done on the load is 4,500 Joules.
A forklift lifts a 900-Newton load 5 meters high. It then carries this load to a horizontal distance of 20 meters. Determine the total work done on the load.
4,500 Joules
9,000 Joules
17,640 Joules
18,000 Joules
27,000 Joules
1 answer
1 answer