a forklift lifts a 100 kg of concrete through a vertical height of 16 m in 20 sec.the power applied to the motor un driving the forklift is 1kw.a) calculate the work done every second in lifting the concrete block.b) what is the power output of the motor?c) what is the efficiency of the motor?

Answer 1

Fc = M*g = 100 * 9.8 = 980 N.

a. Work/s = F*d/t = 980 * 16/20 = 784 J./s. = 784 Watts.

b. Po = Work/s = 784 J/s.

c. Efficiency = Po/Pi = 784Watts/1000Watts = 0.784 = 78.4%.