A force of 9.4N pulls horizontally on a 1.2-kg block that slides on a rough, horizontal surface. This block is connected by a horizontal string to a second block of mass m2 = 2.00kg on the same surface. The coefficient of kinetic friction is μk = 0.25 for both blocks.

Question

A force of 9.4N pulls horizontally on a 1.2-kg block that slides on a rough, horizontal surface. This block is connected by a horizontal string to a second block of mass m2 = 2.00kg on the same surface. The coefficient of kinetic friction is μk = 0.25 for both blocks.
Part A
What is the acceleration of the blocks?
What is the tension in the string?

bobpursley · Answer

net force=total mass*a net force=9.4-.25(total mass)g then the first equation, solve for acceleartion a. tension on the second=masssecond*a+ .25*masssecond*g