A force of 40N is applied at the end of a wire 4m long and produces an extension of 0.24mm. If the diameter of the wire is 2.00mm calculate the stress on the wire and strain in the wire.

With full workings please

4 answers

stress=force/area (n/m^2)

strain=deformation/length (m/m)
If a force of 40newton is applied to the end of a wire 4m long and produces an extension of 0.24mm. If the diameter of the wire is 2mm, calculate the strain energy
F=40n
L=4m
D=2m/100
E=0.24mm/100
A=PIE D2/4=3.14multiplied by 0.02/4
I need the full working problem please