(i) Stress = Force/Area
Area = πr2
r = Diameter/2
Area = π(2.0/2)2
Area = 3.14 x 0.5 x 0.5
Area = 0.785 m2
Stress = 40/0.785
Stress = 50.9 N/m2
(ii) Strain = Extension/Original Length
Strain = 0.24/4
Strain = 0.06 mm/m
(6) A force of 40N is applied at the end of a wire 4m long and produces an extension of 0.24mm.If the diameter of the wire is 2.0mm,calculate the (i) stress on the wire (ii) strain in the wire. With full solution please
1 answer
1 answer