A force of 400.0N is exerted on a 1,250N car while moving it a distance of 3.0m. How much work is done on the car.

3 answers

W=FD
W=(400N)(3.0m)
W=1200N

I don't really get the 1250N car thing. Unless you also need friction, but i need the coefficent for that.
Is there a technological device that doesn't convert one form of energy into another.
I think alan is on the right track. but its 1200 J