a force of 20n applied parallel to the surface of a horizontal table is just sufficient to make a block of mass 4.kg move on the table caculate thd coefficient of friction between the block and the table

1 answer

I'm assuming you're referring to kinetic friction here, in either case (static or kinetic friction) however the following method is able to find the answer.

Friction=mass*g*friction constant
In this case the force of friction is equal and opposite to 20N, so Friction= -20.

-20=mgk
-20=4(-9.8)k
-20=-39.2k
k=.5102 N/m