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A force is applied to a block to move it up a 27° incline. The incline is frictionless. If F = 47.0 N and M = 5.70 kg, what is the magnitude of the acceleration of the block?

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component of weight down slope = m g sin 27 =5.7 * 9.81*sin 27 = 25.4 N
Net force up = 47 -25.4 = 21.6 N
F = m a
21.6 = 5.70 a
a = 3.79 m/s^2

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