work done by Fx = 6 * 6 = 36 Joules
work done by Fy = -1 * 3 = -3 Joules
total work done = 33 Joules
tan F = -1/6 in quadrant 4 so -18.4 deg
tan s = 3/6 in quadrant 1 so 26.6
26.6 + 18.4 = 45 degrees
A force F~ = Fx ˆı + Fy ˆ acts on a particle that
undergoes a displacement of ~s = sx ˆı + sy ˆ
where Fx = 6 N, Fy = −1 N, sx = 6 m, and
sy = 3 m.
Find the work done by the force on the
particle.
Answer in units of J.
Find the angle between F~ and ~s.
Answer in units of ◦
1 answer
1 answer