To find the maximum height the football reaches, we can use the equation given:
\[ h(t) = -16t^2 + 60t + 0 \]
This is a quadratic equation of the form \( h(t) = at^2 + bt + c \), where \( a = -16 \), \( b = 60 \), and \( c = 0 \).
The maximum height of a parabola (which opens downward in this case) occurs at the vertex. The time \( t \) at which the maximum height occurs can be found using the formula:
\[ t = -\frac{b}{2a} \]
Substituting in our values for \( a \) and \( b \):
\[ t = -\frac{60}{2(-16)} = \frac{60}{32} = 1.875 \text{ seconds} \]
Now, we can plug this value of \( t \) back into the height equation to find the maximum height \( h \):
\[ h(1.875) = -16(1.875)^2 + 60(1.875) + 0 \]
Calculating \( (1.875)^2 \):
\[ (1.875)^2 = 3.515625 \]
Now substitute it back into the height equation:
\[ h(1.875) = -16(3.515625) + 60(1.875) \]
Calculating each term:
- \(-16(3.515625) = -56.25\)
- \(60(1.875) = 112.5\)
Now combine these results:
\[ h(1.875) = -56.25 + 112.5 = 56.25 \]
Thus, the maximum height the ball will reach is:
\[ \boxed{56.25} \] feet.