The volume of the gas will increase as the temperature increases.
Using the ideal gas law, we can calculate the new volume:
V2 = V1 * (T2/T1)
V2 = 450 cm3 * (127/27)
V2 = 2250 cm3
A fixed mass of a gas occupies a volume of 450(centimeter cube) at a temperature of 27(degree centigrade) and a pressure of 65 cmHg. Calculate the volume , if the temperature increases to 127(degree centigrade)at constant pressure
2 answers
I think the robot tutor messes this one up too!
I am not overly familiar with physics or chemistry, so I looked
up "Ideal Gas Law" and found a Khan Academy video in which
Mr. Khan explained it in his usual down-to-earth way.
so according to the above, we have
PV = k(nT) , for the given data, n and P remain constant, and k of course
is the constant of proportionality.
Thus we get 2 equations:
65(450) = n*k*27, and
65(V) = n*k*127
dividing them gives us:
450/V = 27/127
V = 450(127/27) , the robot actually had that, but then couldn't do the
V = appr 2116.7 , .... very simple arithmetic
I am not overly familiar with physics or chemistry, so I looked
up "Ideal Gas Law" and found a Khan Academy video in which
Mr. Khan explained it in his usual down-to-earth way.
so according to the above, we have
PV = k(nT) , for the given data, n and P remain constant, and k of course
is the constant of proportionality.
Thus we get 2 equations:
65(450) = n*k*27, and
65(V) = n*k*127
dividing them gives us:
450/V = 27/127
V = 450(127/27) , the robot actually had that, but then couldn't do the
V = appr 2116.7 , .... very simple arithmetic
1 answer