W = m g = 9.81*2.7
x = .036 meter
F = kx
9.81*2.7 = k * .036
solve for k
x = A sin w t
A = .25 meter
w = sqrt (k/m) = sqrt (k/2.7)
w = 2 pi f
so f = w/2pi
A fisherman's scale stretches 3.6 cm when a 2.7-kg fish hangs from it.
(A) What is the spring stiffness constant?
(B) What will be the amplitude and frequency of vibration if the fish is pulled down 2.5 cm more and released so that it vibrates up and down?
What formulas do I need to use? Thanks!!
1 answer
1 answer