A fisherman's scale stretches 2.8 cm. when a 2.1 kg. fish hangs from it. What will be the frequency of vibration if the fish is pulled down and released so that it vibrates up and down?

Answer 1

k = m•g/x = 2.1•9.8/0.028 = 735 N/m.
ω = k/m = 735/2.1 = 0.476 rad/s,
f = ω/2•π =0.476/2•π = 0.076 Hz