A fire hose ejects a stream of water at an angle of 38.3 ° above the horizontal. The water leaves the nozzle with a speed of 29.5 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?

Answer 1

Vo = 29.5 m/s @ 38.3 Deg.
Xo = 29.5*cos38.3 = 23.2 m/s.
Yo = 29.5*sin38.3 = 18.3 m/s.

Tr = (Yf-Yo)/g,
Tr = ( 0-18.3) / -9.8 = 1.87 s = Rise
time or time to reach max ht.

Dx = X0 * Tr = 23.2m/s * 1.87s =43.4 m.
= Dist from bldg.