A fire hose ejects a stream of water at an angle of 31.7 ° above the horizontal. The water leaves the nozzle with a speed of 29.2 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?

Answer 1

Vo = 29.2m/s[31.7o]
Xo = 29.2*Cos31.7 = 24.84 m/s
Yo = 29.2*sin31.7 = 15.34 m/s

Y = Yo + g*Tr = o
Tr = -Yo/g = -15.34/-9.8 = 1.57 s. = Rise time.

Dx = Xo*Tr = 24.84m/s * 1.57s = 38.9 m.