the ball will go up 3s and down 3s
v=gt
where t=3s and g=9.8m/s^2
distance=v0(t)+(1/2)gt^2
where initial velocity (v0)=0
a. Find the speed required to throw a ball straight up and have it return 6 seconds later. Neglect air resistance.
b. How high does the ball go?
Please Help!!
Thanks!! :)
3 answers
it will be 20ft.
It will be 45m