First find the hypotenuse
h^2 = 8^2 + 10^2
..
h = 2√41
which makes the radius of the semi-circle equal to √41
Now find the area of the triangle and add on half the area of the circle
A figure is composed of a right triangle and a semicircle. What is the area of the shaded region?
the triangle is 8 by 10 with no hypontenuse number and a semi circle on the hypotanuse.
Please help!
4 answers
r = hyp./2 = sqrt(8^2+10^2)/2 = 6.4 = radius.
A1 = hb/2 = 8*10/2 = 40 = Area of triangle.
A2 = Shaded area.
A3 = pi*r^2/2 = 3 = 3.14*6.4^2/2 = 64.3 = Area of semi-circle.
A1+A2 = A3
40 + A2 = 64.3
A2 =
A1 = hb/2 = 8*10/2 = 40 = Area of triangle.
A2 = Shaded area.
A3 = pi*r^2/2 = 3 = 3.14*6.4^2/2 = 64.3 = Area of semi-circle.
A1+A2 = A3
40 + A2 = 64.3
A2 =
@henry2 TYSM!
You are welcome.
4 answers