A farmer drives a 0.100 kg iron spike with a 2.00 kg sledge hammer. The sledge hammer moves at a constant speed of 3.99 m/s until it comes to rest on the spike after each swing. Assuming all the energy is absorbed by the nail, and ignoring the work done by the nail on the hammer, how much would the nail's temperature rise after 10 successive swings?

Answer 1

work done on hammer in 10 swings
= 10(1/2) m v^2 = 5(2)(3.99)^2
= 159 Joules

I do not know specific heat of iron off hand
159 Joules = Ciron (2 kg) (delta T)

Answer 2

E=Q
Q=mct
E=1/2mv^2*10
5mv^2=mct
5*2*3.99^2=0.1*450*t
T=3.53. C