the answer will be Q1 (5)
Q2 (0.754)
Good Luck :)
A family consists of ten children. Assuming that the sexes are equally probable,
find the expected number of boys in the family.
What is the probability that the expected number of boys will not occur?
(Not sure where to start) I got partial credit and I answered 5 (Question 1) and 1/2 (Question 2)
3 answers
How is question 2= 0.754?
The second question is 0.754 because of this equation:
(10C5)= (0.5^5)(0.5)^5
= 0.246
P(E')= 1-P(E)
= 1-0.246
= 0.754
(10C5)= (0.5^5)(0.5)^5
= 0.246
P(E')= 1-P(E)
= 1-0.246
= 0.754
0 answers