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a fair spinner has 11 equal sections 4 red 4 blue 3 green

it is spun twice
what is the probability of getting not green then green

2 answers

well, if 3 of the 11 are green, then 8 must be not-green.

Prob(not green, then green) = (8/11)(3/11) = 24/121

HHHHHEEEELLLPPPP

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