a fair number cube is rolled. what is the probability of getting a number less than 6?
2 answers
well, 5 of the 6 numbers are less than 6, so ...
Sample space (S)={1,2,3,4,5,6}
n(S)=6
Let a be the event of getting number less than 6.
a={1,2,3,4,5}
Therefore n(a)=5
P(d)=n(a)/n(s)
=5/6
n(S)=6
Let a be the event of getting number less than 6.
a={1,2,3,4,5}
Therefore n(a)=5
P(d)=n(a)/n(s)
=5/6
1 answer