To determine the diver's elevation when he is \( \frac{2}{3} \) of the way down to the treasure located 97.2 feet below the surface, we can first calculate the distance the diver descends.
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Calculate how far down he goes: \[ \text{Distance descended} = \frac{2}{3} \times 97.2 \text{ ft} \] \[ \text{Distance descended} = \frac{2 \times 97.2}{3} = \frac{194.4}{3} = 64.8 \text{ ft} \]
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Since the diver starts at the surface (0 ft elevation), his elevation after descending 64.8 ft will be: \[ \text{Elevation} = 0 \text{ ft} - 64.8 \text{ ft} = -64.8 \text{ ft} \]
Therefore, the diver's elevation when he is \( \frac{2}{3} \) of the way down is \( -64.8 \) ft.
The correct answer is: A. −64.8 ft.
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