A diver searches for a sunken treasure that is 97.2 feet below the surface. What is the diver's elevation when he is 2/3 of the way down

1 answer

To find the diver's elevation when he is 2/3 of the way down to the treasure located 97.2 feet below the surface, we can first calculate how far down the diver goes when he is 2/3 of the way to the treasure.

  1. Calculate 2/3 of the distance to the treasure: \[ \text{Distance down} = \frac{2}{3} \times 97.2 \text{ feet} = \frac{2 \times 97.2}{3} = \frac{194.4}{3} = 64.8 \text{ feet} \]

  2. Since the diver is going down, we find his elevation relative to the surface: \[ \text{Elevation} = 0 - 64.8 \text{ feet} = -64.8 \text{ feet} \]

Thus, the diver's elevation when he is 2/3 of the way down is -64.8 feet.