A diver searches for a sunken treasure that is 97.2 feet below the surface What is the divers elevation when he is 2/3 of the way down?

Answer 1

To find the diver's elevation when he is \( \frac{2}{3} \) of the way down to a depth of 97.2 feet, we first calculate the distance he has descended.

1. Calculate \( \frac{2}{3} \) of 97.2 feet: \[ \frac{2}{3} \times 97.2 = \frac{2 \times 97.2}{3} = \frac{194.4}{3} = 64.8 \text{ feet} \]

So, the diver descends 64.8 feet.

2. To find the diver's elevation at this point, we can subtract this distance from the surface level. Since we define the surface level as 0 feet, the elevation at 64.8 feet down is: \[ 0 - 64.8 = -64.8 \text{ feet} \]

Thus, the diver's elevation when he is \( \frac{2}{3} \) of the way down is -64.8 feet.