To find the diver's elevation when he is \( \frac{2}{3} \) of the way down to the treasure, you first need to calculate how far down that is from the surface.
The total depth is 97.2 feet. If the diver is \( \frac{2}{3} \) of the way down, you calculate the distance as follows:
\[ \text{Distance down} = \frac{2}{3} \times 97.2 \text{ ft} = 64.8 \text{ ft} \]
Now, since the surface is considered 0 feet, and being 64.8 feet down means his elevation (which will be negative) is:
\[ \text{Elevation} = -64.8 \text{ ft} \]
So the diver's elevation when he is \( \frac{2}{3} \) of the way down is:
\(-64.8 , \text{ft}\)
Answer: -64.8 ft
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