x = Xi + Vi t + (1/2) a t^2
x = .5 (950 deg/s^2)(.15s)^2
= 10.7 degrees
A diver is trying a new more and is attempting to increase his angular acceleration in order to increase the angular displacement and thus produce more rotations from a standing start on the board the diver accelerates at 950 degree/s/s.what is the angular displacement over 0.15s?
3 answers
Could u explain Damon how do u got .5 for xi
Hint the tutor gave for this problem is to use more than one equation to get this Damon thanks for answering could u explain these please in detail