A diver in midair has an angular velocity of 6.0 rad/s and a moment of inertia of 1.2 kg·m2. He then pulls is arms and legs into a tuck position and his angular velocity increases to 12 rad/s. The net external torque acting on the diver is zero. What is his moment of inertia in the tuck position?

Answer 1

The Conservation of Angular Momentum will be conserved. (Hint: it states that the net external torque acting on the diver is zero.)

Angular Momentum =
moment of inertia x angular velocity

(6.0) (1.2) = 12x
7.2 = 12x
x = 0.6 kg·m^2

Answer 2

Ur dumb :3

Answer 3

0.6