A dihybrid cross displays the possible allele combinations for two different traits. In pea plants, seed can be yellow (dominant) or green (recessive). They can also have a smooth seed texture (dominant) or wrinkled (recessive). Using the diagram below, identify the probability (as a percentage) of offspring with YELLOW SEEDS and WRINKLED TEXTURE.

Question

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1 point
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9/16 (56.25%)
12/16 (75%)
3/16 (18.75%)
4/16 (25%)

Answer 1

In a dihybrid cross for pea plants involving the traits of seed color (yellow vs. green) and seed texture (smooth vs. wrinkled), we can use a Punnett square to determine the possible allele combinations.

For two traits, where:

• Yellow seeds (Y) are dominant over green seeds (y)
• Smooth texture (S) is dominant over wrinkled texture (s)

The possible combinations for the alleles from heterozygous parents (YySs x YySs) would yield the following phenotypic ratios:

1. Yellow seeds, smooth texture (YYSS, YySS, YYSs, YySs) = 9/16
2. Yellow seeds, wrinkled texture (YYss, Yyss) = 3/16
3. Green seeds, smooth texture (yySS, yySs) = 3/16
4. Green seeds, wrinkled texture (yyss) = 1/16

To find the probability of offspring with yellow seeds (Y) and wrinkled texture (ss):

• This combination is represented by Yyss and YYss, which totals 3 out of 16 possible combinations.

Thus, the probability of offspring having yellow seeds and wrinkled texture is:

\[ \frac{3}{16} \times 100% = 18.75% \]

So, the correct answer is 3/16 (18.75%).