Based on the diagram below, the probability of offspring with green seeds and smooth texture is 1/16 , which is equivalent to 6.25%.
Diagram:
Y = Yellow seed (dominant)
y = Green seed (recessive)
S = Smooth texture (dominant)
s = Wrinkled texture (recessive)
Punnett Square:
| YS | Ys | yS | ys |
_____|_____|_____|_____|_____|
YS | YSYS | YsS | YsS | YsS |
_____|_____|_____|_____|_____|
Ys | YSYS | YsS | ySs | ysS |
_____|_____|_____|_____|_____|
yS | YsS | ysS | ySs | ysS |
_____|_____|_____|_____|_____|
ys | YsS | ysS | ysS | yss |
_____|_____|_____|_____|_____|
Out of the 16 possible allele combinations, there is only one combination that results in offspring with green seeds and smooth texture (ysS). Therefore, the probability is 1/16 or 6.25%.
So, the correct answer is:
1 point1/16 (6.25%)
A dihybrid cross displays the possible allele combinations for two different traits. In pea plants, seed can be yellow (dominant) or green (recessive). They can also have a smooth seed texture (dominant) or wrinkled (recessive). Using the diagram below, identify the probability (as a percentage) of offspring with GREEN SEEDS AND SMOOTH TEXTURE.
*
1 point1/16 (6.25%)
8/16 (50%)
3/16 (18.75%)
4/16 (25%)
1 answer