Asked by Mike
A diagram shows a straight line graph of In y against x,passing through the point (0,2) and having gradient -3/2 .
The variables x and y are connected by the equation y=pq^x ,where p and q are constants
Find (ii)the equation relating x and y
Thank you!
The variables x and y are connected by the equation y=pq^x ,where p and q are constants
Find (ii)the equation relating x and y
Thank you!
Answers
Answered by
oobleck
well, we have
lny = -3/2 x + 2
so
y = e^(-3/2 x + 2)
= e^2 * e^(-3/2 x)
= e^2 * (e^(-3/2))^x
lny = -3/2 x + 2
so
y = e^(-3/2 x + 2)
= e^2 * e^(-3/2 x)
= e^2 * (e^(-3/2))^x
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