To find the area of the deck only, we need to calculate the area of the outer rectangle formed by the deck.
The length of the outer rectangle will be the length of the pool plus twice the width of the deck on either side:
Length of outer rectangle = 20 ft + 2 * 6 ft = 20 ft + 12 ft = 32 ft
Similarly, the width of the outer rectangle will be the width of the pool plus twice the width of the deck on either end:
Width of outer rectangle = 12 ft + 2 * 6 ft = 12 ft + 12 ft = 24 ft
Therefore, the area of the deck only is the area of the outer rectangle minus the area of the pool:
Area of deck only = Area of outer rectangle - Area of pool
= (32 ft * 24 ft) - (20 ft * 12 ft)
= 768 ft² - 240 ft²
= 528 ft²
So, the area of the deck only is 528 square feet.
A deck is being built around a rectangular swimming pool. The swimming pool is 20 ft × 12 ft and the deck has a uniform width of 6 ft. What is the area of the deck only?
3 answers
A gym membership costs $25 to join and $14 each month. Write and use an algebraic expression to find the cost of the gym membership for 6 months.
To find the cost of the gym membership for 6 months, we need to multiply the monthly cost by 6 and add the initial joining cost.
Let's use the variables J and M to represent the joining cost and monthly cost, respectively.
J = $25 (joining cost)
M = $14 (monthly cost)
Then, the algebraic expression to find the cost of the gym membership for 6 months would be:
6M + J = 6 * $14 + $25
= $84 + $25
= $109
Therefore, the cost of the gym membership for 6 months would be $109.
Let's use the variables J and M to represent the joining cost and monthly cost, respectively.
J = $25 (joining cost)
M = $14 (monthly cost)
Then, the algebraic expression to find the cost of the gym membership for 6 months would be:
6M + J = 6 * $14 + $25
= $84 + $25
= $109
Therefore, the cost of the gym membership for 6 months would be $109.