A deck is being built around a rectangular swimming pool. The swimming pool is 20 ft × 12 ft and the deck has a uniform width of 6 ft. What is the area of the deck only?

Question

(1 point)

Answer 1

To find the area of the deck, we need to subtract the area of the pool from the area of the pool plus the deck.

The area of the pool is length times width, which is 20 ft × 12 ft = <<20*12=240>>240 ft².

The deck has a uniform width of 6 ft around all sides of the pool, so we can add 6 ft to the length and width of the pool to find the dimensions of the pool plus the deck.

The length of the pool plus the deck is 20 ft + 2×6 ft = 32 ft.
The width of the pool plus the deck is 12 ft + 2×6 ft = 24 ft.

The area of the pool plus the deck is 32 ft × 24 ft = <<32*24=768>>768 ft².

To find the area of the deck only, we subtract the area of the pool from the area of the pool plus the deck:
768 ft² - 240 ft² = <<768-240=528>>528 ft².

Therefore, the area of the deck only is 528 ft². Answer: \boxed{528}.

Answer 2

is this true

Answer 3

Yes, the calculations provided are correct. The area of the deck only is indeed 528 ft².