(x-4)(104/x+6) = 104+22
x = 13
So, he bought 13 at 8 cents, and sold 9 at 14 cents
A dealer bought some grapefruits for $1.04. After throwing away 4 bad ones, he sold the other ones at 6 cents apiece more than he had paid for them and made a profit of $0.22. How many did he buy?
3 answers
can you show how the equation would be solved?
(x-4)(104/x+6) = 126
104 + 6x - 416/x -24 - 126 = 0
6x - 46 - 416/x = 0
times x
6x^2 - 23x - 416 = 0
3x^2 - 11x - 208 = 0
(x - 13)(3x + 16) = 0
x = 13 or x = -16/3, but x can't be negative, so
x = 13
104 + 6x - 416/x -24 - 126 = 0
6x - 46 - 416/x = 0
times x
6x^2 - 23x - 416 = 0
3x^2 - 11x - 208 = 0
(x - 13)(3x + 16) = 0
x = 13 or x = -16/3, but x can't be negative, so
x = 13