The horizontal velocity component is 33.3 cos54 = 19.57 m/s
The daredevil reaches the 41.8 m distance in T = 41.8/19.57 = 2.14 seconds
His height above the ground at that time can be calculated using
Y = 33.3 sin54*T - (g/2)*T^2.
A daredevil is shot out of a cannon at 54 degrees to the horizontal with an initial speed of 33.3 m/s. A net is positioned a horizontal distance of 41.8 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil?
The acceleration of gravity is 9.8 m/s^2.
Answer in units of m.
1 answer