H(x)=vi*t - 1/2 9.8 t^2
x=41.2 vi=27.5*sin44.9
now for t:
d(x)=27.5*cos44.9*t
but d(x)=41.2 solve for t, put it int the first equation, then solve for h(x).
A daredevil is shot out of a cannon at 44.9◦ to the horizontal with an initial speed of 27.5 m/s. A net is positioned at a horizontal dis- tance of 41.2 m from the cannon from which the daredevil is shot.
The acceleration of gravity is 9.81 m/s2 .
At what height above the cannon’s mouth should the net be placed in order to catch the daredevil?
Answer in units of m.
1 answer