A dam 143 m above a hydroelectric generator holds 1.6 x 1015 L of water. If the generator is taken to be at a height of 0 m, how much potential energy is stored in the dam?

Answer 1

I assume you made a typo and mean 1.6 * 10^15 Liters

1 liter water = 1 kg
a pint is a pound the world around :)

m g h = 1.6*10^15 kg * 9.81 m/s^2 * 143 m

= 2245 * 10^15
= 2.245 * 10^18 Joules

Answer 2

PE=mgh

=1.6*10^15*9.8*143
=2242.24*10^15
=2.242*10^18